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Class 11 Question Answers — Physics — Motion

Applications of Newton’s Laws of Motion

There are two kinds of problems in classical mechanics :(a) To find unknown forces acting on a body, given the body’s acceleration. (b) To predict the future motion of a body, given the body’s initial position and vel...

Class 11 Subject: Physics Topic: Motion
A drunkard walking in a narrow lane takes 5 steps forward and 3 steps backward, followed again by 5 steps forward and 3 steps backward, and so on. Each step is...

In the above question it is given that:Distance covered with 1 step = 1 min Time taken = 1 sTime taken to move first 5 m forward = 5 sTime taken to move 3 m backward =3 sNet distance covered = 5 3 = 2mNet time taken to c...

Class 11 Subject: Physics Topic: Motion
A woman starts from her home at 9.00 am, walks with a speed of on a straight road up to her office 2.5 km away, stays at the office up to 5.00 pm, and returns h...

: In the above question it is given that:Speed of the woman = 5 km/hrDistance between her office and home = 2.5 kmTime Taken = distance / speed= 2.5/5 = 0.5 h = 30 min It is given that she covers the same distance in th...

Class 11 Subject: Physics Topic: Motion
In which of the following examples of motion, can the body be considered approximately a point object: (a) A railway carriage moving without jerks between two...

(a) A railway carriage moving without jerks between two stations.Ans: As the size of a carriage is very small as compared to the distance between two stations, the carriage can be treated as a point sized object. (b)...

Class 11 Subject: Physics Topic: Motion
State Newton’s three laws with examples.

·         1st Law: Object remains at rest or uniform motion unless a force acts. (e.g., passenger jerks forward in braking car)·         2nd Law: F=ma -  Acceleration is proportional to force. (e.g., heavier carts n...

Class 11 Subject: Physics Topic: Motion
Derive equations of motion graphically.

Let object start with velocity u and constant acceleration a Using area under v–t graph:1.     v=u+at2.     s=ut+1/2at^2 3.     v^2=u^2+2as All derived using geometric interpretation of motion.

Class 11 Subject: Physics Topic: Motion
Subject Wise Question Answers Class 11

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