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In the above question it is given that:
Distance covered with 1 step = 1 min
Time taken = 1 s
Time taken to move first 5 m forward = 5 s
Time taken to move 3 m backward =3 s
Net distance covered = 5 3 = 2m
Net time taken to cover 2m = 8s
Hence,
Drunkard covers 2 min 8 s
Drunkard covered 4 min 16 sec
Drunkard covered 6 min 24 s
Drunkard covered 8 min 32 s
In the next 5s , the drunkard will cover a
distance of 5m and a total distance of 13 m and then fall into the pit.
Net time taken by the drunkard to cover km 13 km
= 32+ 5 = 37 s
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